7(d-2)-3d=5-2(d+3)+4d

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Solution for 7(d-2)-3d=5-2(d+3)+4d equation: 



7(d-2)-3d=5-2(d+3)+4d

We move all terms to the left:

7(d-2)-3d-(5-2(d+3)+4d)=0

We add all the numbers together, and all the variables

-3d+7(d-2)-(5-2(d+3)+4d)=0

We multiply parentheses

-3d+7d-(5-2(d+3)+4d)-14=0



We calculate terms in parentheses: -(5-2(d+3)+4d), so:

5-2(d+3)+4d

determiningTheFunctionDomain
-2(d+3)+4d+5

We add all the numbers together, and all the variables

4d-2(d+3)+5

We multiply parentheses

4d-2d-6+5

We add all the numbers together, and all the variables

2d-1

Back to the equation:

-(2d-1)



We add all the numbers together, and all the variables

4d-(2d-1)-14=0

We get rid of parentheses

4d-2d+1-14=0

We add all the numbers together, and all the variables

2d-13=0

We move all terms containing d to the left, all other terms to the right

2d=13

d=13/2

d=6+1/2

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