7(d-2)=5(d-3)+2d+1

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Solution for 7(d-2)=5(d-3)+2d+1 equation: 



7(d-2)=5(d-3)+2d+1

We move all terms to the left:

7(d-2)-(5(d-3)+2d+1)=0

We multiply parentheses

7d-(5(d-3)+2d+1)-14=0



We calculate terms in parentheses: -(5(d-3)+2d+1), so:

5(d-3)+2d+1

We add all the numbers together, and all the variables

2d+5(d-3)+1

We multiply parentheses

2d+5d-15+1

We add all the numbers together, and all the variables

7d-14

Back to the equation:

-(7d-14)



We get rid of parentheses

7d-7d+14-14=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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