7(d-4)+12=5

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Solution for 7(d-4)+12=5 equation: 



7(d-4)+12=5

We move all terms to the left:

7(d-4)+12-(5)=0

We add all the numbers together, and all the variables

7(d-4)+7=0

We multiply parentheses

7d-28+7=0

We add all the numbers together, and all the variables

7d-21=0

We move all terms containing d to the left, all other terms to the right

7d=21

d=21/7

d=3

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