7(e-1)-8=4(e+2)+4

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Solution for 7(e-1)-8=4(e+2)+4 equation: 



7(e-1)-8=4(e+2)+4

We move all terms to the left:

7(e-1)-8-(4(e+2)+4)=0

We multiply parentheses

7e-(4(e+2)+4)-7-8=0



We calculate terms in parentheses: -(4(e+2)+4), so:

4(e+2)+4

We multiply parentheses

4e+8+4

We add all the numbers together, and all the variables

4e+12

Back to the equation:

-(4e+12)



We add all the numbers together, and all the variables

7e-(4e+12)-15=0

We get rid of parentheses

7e-4e-12-15=0

We add all the numbers together, and all the variables

3e-27=0

We move all terms containing e to the left, all other terms to the right

3e=27

e=27/3

e=9

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