7(f-2)+4=2(2f+4)

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Solution for 7(f-2)+4=2(2f+4) equation: 



7(f-2)+4=2(2f+4)

We move all terms to the left:

7(f-2)+4-(2(2f+4))=0

We multiply parentheses

7f-(2(2f+4))-14+4=0



We calculate terms in parentheses: -(2(2f+4)), so:

2(2f+4)

We multiply parentheses

4f+8

Back to the equation:

-(4f+8)



We add all the numbers together, and all the variables

7f-(4f+8)-10=0

We get rid of parentheses

7f-4f-8-10=0

We add all the numbers together, and all the variables

3f-18=0

We move all terms containing f to the left, all other terms to the right

3f=18

f=18/3

f=6

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