7(f-3)+1=f+16

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Solution for 7(f-3)+1=f+16 equation: 



7(f-3)+1=f+16

We move all terms to the left:

7(f-3)+1-(f+16)=0

We multiply parentheses

7f-(f+16)-21+1=0

We get rid of parentheses

7f-f-16-21+1=0

We add all the numbers together, and all the variables

6f-36=0

We move all terms containing f to the left, all other terms to the right

6f=36

f=36/6

f=6

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