7(h+2)+1=4h+3(5+h)

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Solution for 7(h+2)+1=4h+3(5+h) equation:


Simplifying
7(h + 2) + 1 = 4h + 3(5 + h)

Reorder the terms:
7(2 + h) + 1 = 4h + 3(5 + h)
(2 * 7 + h * 7) + 1 = 4h + 3(5 + h)
(14 + 7h) + 1 = 4h + 3(5 + h)

Reorder the terms:
14 + 1 + 7h = 4h + 3(5 + h)

Combine like terms: 14 + 1 = 15
15 + 7h = 4h + 3(5 + h)
15 + 7h = 4h + (5 * 3 + h * 3)
15 + 7h = 4h + (15 + 3h)

Reorder the terms:
15 + 7h = 15 + 4h + 3h

Combine like terms: 4h + 3h = 7h
15 + 7h = 15 + 7h

Add '-15' to each side of the equation.
15 + -15 + 7h = 15 + -15 + 7h

Combine like terms: 15 + -15 = 0
0 + 7h = 15 + -15 + 7h
7h = 15 + -15 + 7h

Combine like terms: 15 + -15 = 0
7h = 0 + 7h
7h = 7h

Add '-7h' to each side of the equation.
7h + -7h = 7h + -7h

Combine like terms: 7h + -7h = 0
0 = 7h + -7h

Combine like terms: 7h + -7h = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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