7(h+2)-6=2(2h-3)-4

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Solution for 7(h+2)-6=2(2h-3)-4 equation: 



7(h+2)-6=2(2h-3)-4

We move all terms to the left:

7(h+2)-6-(2(2h-3)-4)=0

We multiply parentheses

7h-(2(2h-3)-4)+14-6=0



We calculate terms in parentheses: -(2(2h-3)-4), so:

2(2h-3)-4

We multiply parentheses

4h-6-4

We add all the numbers together, and all the variables

4h-10

Back to the equation:

-(4h-10)



We add all the numbers together, and all the variables

7h-(4h-10)+8=0

We get rid of parentheses

7h-4h+10+8=0

We add all the numbers together, and all the variables

3h+18=0

We move all terms containing h to the left, all other terms to the right

3h=-18

h=-18/3

h=-6

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