7(h-2)+3=2(h+2)-2

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Solution for 7(h-2)+3=2(h+2)-2 equation: 



7(h-2)+3=2(h+2)-2

We move all terms to the left:

7(h-2)+3-(2(h+2)-2)=0

We multiply parentheses

7h-(2(h+2)-2)-14+3=0



We calculate terms in parentheses: -(2(h+2)-2), so:

2(h+2)-2

We multiply parentheses

2h+4-2

We add all the numbers together, and all the variables

2h+2

Back to the equation:

-(2h+2)



We add all the numbers together, and all the variables

7h-(2h+2)-11=0

We get rid of parentheses

7h-2h-2-11=0

We add all the numbers together, and all the variables

5h-13=0

We move all terms containing h to the left, all other terms to the right

5h=13

h=13/5

h=2+3/5

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