7(j+1)+11=5(j+3)+9

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Solution for 7(j+1)+11=5(j+3)+9 equation:


Simplifying
7(j + 1) + 11 = 5(j + 3) + 9

Reorder the terms:
7(1 + j) + 11 = 5(j + 3) + 9
(1 * 7 + j * 7) + 11 = 5(j + 3) + 9
(7 + 7j) + 11 = 5(j + 3) + 9

Reorder the terms:
7 + 11 + 7j = 5(j + 3) + 9

Combine like terms: 7 + 11 = 18
18 + 7j = 5(j + 3) + 9

Reorder the terms:
18 + 7j = 5(3 + j) + 9
18 + 7j = (3 * 5 + j * 5) + 9
18 + 7j = (15 + 5j) + 9

Reorder the terms:
18 + 7j = 15 + 9 + 5j

Combine like terms: 15 + 9 = 24
18 + 7j = 24 + 5j

Solving
18 + 7j = 24 + 5j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-5j' to each side of the equation.
18 + 7j + -5j = 24 + 5j + -5j

Combine like terms: 7j + -5j = 2j
18 + 2j = 24 + 5j + -5j

Combine like terms: 5j + -5j = 0
18 + 2j = 24 + 0
18 + 2j = 24

Add '-18' to each side of the equation.
18 + -18 + 2j = 24 + -18

Combine like terms: 18 + -18 = 0
0 + 2j = 24 + -18
2j = 24 + -18

Combine like terms: 24 + -18 = 6
2j = 6

Divide each side by '2'.
j = 3

Simplifying
j = 3

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