7(j+3)=49

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Solution for 7(j+3)=49 equation: 



7(j+3)=49

We move all terms to the left:

7(j+3)-(49)=0

We multiply parentheses

7j+21-49=0

We add all the numbers together, and all the variables

7j-28=0

We move all terms containing j to the left, all other terms to the right

7j=28

j=28/7

j=4

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