7(j+3)=6(j-3)

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Solution for 7(j+3)=6(j-3) equation: 


Simplifying
7(j + 3) = 6(j + -3)

Reorder the terms:
7(3 + j) = 6(j + -3)
(3 * 7 + j * 7) = 6(j + -3)
(21 + 7j) = 6(j + -3)

Reorder the terms:
21 + 7j = 6(-3 + j)
21 + 7j = (-3 * 6 + j * 6)
21 + 7j = (-18 + 6j)

Solving
21 + 7j = -18 + 6j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-6j' to each side of the equation.
21 + 7j + -6j = -18 + 6j + -6j

Combine like terms: 7j + -6j = 1j
21 + 1j = -18 + 6j + -6j

Combine like terms: 6j + -6j = 0
21 + 1j = -18 + 0
21 + 1j = -18

Add '-21' to each side of the equation.
21 + -21 + 1j = -18 + -21

Combine like terms: 21 + -21 = 0
0 + 1j = -18 + -21
1j = -18 + -21

Combine like terms: -18 + -21 = -39
1j = -39

Divide each side by '1'.
j = -39

Simplifying
j = -39

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