7(j+3)=70

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Solution for 7(j+3)=70 equation: 



7(j+3)=70

We move all terms to the left:

7(j+3)-(70)=0

We multiply parentheses

7j+21-70=0

We add all the numbers together, and all the variables

7j-49=0

We move all terms containing j to the left, all other terms to the right

7j=49

j=49/7

j=7

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