7(j-15)=7(6j+5)

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Solution for 7(j-15)=7(6j+5) equation: 



7(j-15)=7(6j+5)

We move all terms to the left:

7(j-15)-(7(6j+5))=0

We multiply parentheses

7j-(7(6j+5))-105=0



We calculate terms in parentheses: -(7(6j+5)), so:

7(6j+5)

We multiply parentheses

42j+35

Back to the equation:

-(42j+35)



We get rid of parentheses

7j-42j-35-105=0

We add all the numbers together, and all the variables

-35j-140=0

We move all terms containing j to the left, all other terms to the right

-35j=140

j=140/-35

j=-4

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