7(k+3)+4(3k-5)=

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Solution for 7(k+3)+4(3k-5)= equation:


7(k+3)+4(3k-5)=0

We simplify the equation to the form, which is simple to understand 
7(k+3)+4(3k-5)=0

Reorder the terms in parentheses
+(+7k+21)+4*(3k-5)=0

Remove unnecessary parentheses
+7k+21+4+*(+3k-5+)=0

Reorder the terms in parentheses
+7k+21+(+12k-20)=0

Remove unnecessary parentheses
+7k+21+12k-20=0

We move all terms containing k to the left and all other terms to the right. 
+7k+12k=0-21+20

We simplify left and right side of the equation. 
+19k=-1

We divide both sides of the equation by 19 to get k. 
k=-0.0526315789474

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