7(k+3)-7(3-2k)=-3k+5k

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Solution for 7(k+3)-7(3-2k)=-3k+5k equation: 



7(k+3)-7(3-2k)=-3k+5k

We move all terms to the left:

7(k+3)-7(3-2k)-(-3k+5k)=0

We add all the numbers together, and all the variables

7(k+3)-7(-2k+3)-(+2k)=0

We multiply parentheses

7k+14k-(+2k)+21-21=0

We get rid of parentheses

7k+14k-2k+21-21=0

We add all the numbers together, and all the variables

19k=0

k=0/19

k=0

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