7(k+3)=45-3(12-k)=

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Solution for 7(k+3)=45-3(12-k)= equation: 



7(k+3)=45-3(12-k)=

We move all terms to the left:

7(k+3)-(45-3(12-k))=0

We add all the numbers together, and all the variables

7(k+3)-(45-3(-1k+12))=0

We multiply parentheses

7k-(45-3(-1k+12))+21=0



We calculate terms in parentheses: -(45-3(-1k+12)), so:

45-3(-1k+12)

determiningTheFunctionDomain
-3(-1k+12)+45

We multiply parentheses

3k-36+45

We add all the numbers together, and all the variables

3k+9

Back to the equation:

-(3k+9)



We get rid of parentheses

7k-3k-9+21=0

We add all the numbers together, and all the variables

4k+12=0

We move all terms containing k to the left, all other terms to the right

4k=-12

k=-12/4

k=-3

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