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7(k-2)-12=3(k+1)+19
We move all terms to the left:
7(k-2)-12-(3(k+1)+19)=0
We multiply parentheses
7k-(3(k+1)+19)-14-12=0
We calculate terms in parentheses: -(3(k+1)+19), so:We add all the numbers together, and all the variables
3(k+1)+19
We multiply parentheses
3k+3+19
We add all the numbers together, and all the variables
3k+22
Back to the equation:
-(3k+22)
7k-(3k+22)-26=0
We get rid of parentheses
7k-3k-22-26=0
We add all the numbers together, and all the variables
4k-48=0
We move all terms containing k to the left, all other terms to the right
4k=48
k=48/4
k=12
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