7(k-2)-6=-2(2k-3)+9k

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Solution for 7(k-2)-6=-2(2k-3)+9k equation: 



7(k-2)-6=-2(2k-3)+9k

We move all terms to the left:

7(k-2)-6-(-2(2k-3)+9k)=0

We multiply parentheses

7k-(-2(2k-3)+9k)-14-6=0



We calculate terms in parentheses: -(-2(2k-3)+9k), so:

-2(2k-3)+9k

We add all the numbers together, and all the variables

9k-2(2k-3)

We multiply parentheses

9k-4k+6

We add all the numbers together, and all the variables

5k+6

Back to the equation:

-(5k+6)



We add all the numbers together, and all the variables

7k-(5k+6)-20=0

We get rid of parentheses

7k-5k-6-20=0

We add all the numbers together, and all the variables

2k-26=0

We move all terms containing k to the left, all other terms to the right

2k=26

k=26/2

k=13

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