7(k-3)=2(k-9)+2k

Solution for 7(k-3)=2(k-9)+2k equation:

7(k-3)=2(k-9)+2k

We move all terms to the left:

7(k-3)-(2(k-9)+2k)=0

We multiply parentheses

7k-(2(k-9)+2k)-21=0


We calculate terms in parentheses: -(2(k-9)+2k), so:

2(k-9)+2k

We add all the numbers together, and all the variables

2k+2(k-9)

We multiply parentheses

2k+2k-18

We add all the numbers together, and all the variables

4k-18

Back to the equation:

-(4k-18)


We get rid of parentheses

7k-4k+18-21=0

We add all the numbers together, and all the variables

3k-3=0

We move all terms containing k to the left, all other terms to the right

3k=3

k=3/3

k=1