7(k-8)-(6k-8)=3

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Solution for 7(k-8)-(6k-8)=3 equation: 



7(k-8)-(6k-8)=3

We move all terms to the left:

7(k-8)-(6k-8)-(3)=0

We multiply parentheses

7k-(6k-8)-56-3=0

We get rid of parentheses

7k-6k+8-56-3=0

We add all the numbers together, and all the variables

k-51=0

We move all terms containing k to the left, all other terms to the right

k=51

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