7(k-8)=3(2k-4)

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Solution for 7(k-8)=3(2k-4) equation: 



7(k-8)=3(2k-4)

We move all terms to the left:

7(k-8)-(3(2k-4))=0

We multiply parentheses

7k-(3(2k-4))-56=0



We calculate terms in parentheses: -(3(2k-4)), so:

3(2k-4)

We multiply parentheses

6k-12

Back to the equation:

-(6k-12)



We get rid of parentheses

7k-6k+12-56=0

We add all the numbers together, and all the variables

k-44=0

We move all terms containing k to the left, all other terms to the right

k=44

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