7(m+-6)*m=8

Solution for 7(m+-6)*m=8 equation:

7(m+-6)*m=8

We move all terms to the left:

7(m+-6)*m-(8)=0

We add all the numbers together, and all the variables

7(m-6)*m-8=0

We multiply parentheses

7m^2-42m-8=0

a = 7; b = -42; c = -8;
Δ = b2-4ac
Δ = -422-4·7·(-8)
Δ = 1988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1988}=\sqrt{4*497}=\sqrt{4}*\sqrt{497}=2\sqrt{497}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{497}}{2*7}=\frac{42-2\sqrt{497}}{14}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{497}}{2*7}=\frac{42+2\sqrt{497}}{14}
$