7(m-10)+110=4(m-25)+8

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Solution for 7(m-10)+110=4(m-25)+8 equation: 



7(m-10)+110=4(m-25)+8

We move all terms to the left:

7(m-10)+110-(4(m-25)+8)=0

We multiply parentheses

7m-(4(m-25)+8)-70+110=0



We calculate terms in parentheses: -(4(m-25)+8), so:

4(m-25)+8

We multiply parentheses

4m-100+8

We add all the numbers together, and all the variables

4m-92

Back to the equation:

-(4m-92)



We add all the numbers together, and all the variables

7m-(4m-92)+40=0

We get rid of parentheses

7m-4m+92+40=0

We add all the numbers together, and all the variables

3m+132=0

We move all terms containing m to the left, all other terms to the right

3m=-132

m=-132/3

m=-44

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