7(m-4)-2m=19+3(m+3)

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Solution for 7(m-4)-2m=19+3(m+3) equation: 



7(m-4)-2m=19+3(m+3)

We move all terms to the left:

7(m-4)-2m-(19+3(m+3))=0

We add all the numbers together, and all the variables

-2m+7(m-4)-(19+3(m+3))=0

We multiply parentheses

-2m+7m-(19+3(m+3))-28=0



We calculate terms in parentheses: -(19+3(m+3)), so:

19+3(m+3)

determiningTheFunctionDomain
3(m+3)+19

We multiply parentheses

3m+9+19

We add all the numbers together, and all the variables

3m+28

Back to the equation:

-(3m+28)



We add all the numbers together, and all the variables

5m-(3m+28)-28=0

We get rid of parentheses

5m-3m-28-28=0

We add all the numbers together, and all the variables

2m-56=0

We move all terms containing m to the left, all other terms to the right

2m=56

m=56/2

m=28

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