7(m-5)=13(3-m)+2m

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Solution for 7(m-5)=13(3-m)+2m equation: 



7(m-5)=13(3-m)+2m

We move all terms to the left:

7(m-5)-(13(3-m)+2m)=0

We add all the numbers together, and all the variables

7(m-5)-(13(-1m+3)+2m)=0

We multiply parentheses

7m-(13(-1m+3)+2m)-35=0



We calculate terms in parentheses: -(13(-1m+3)+2m), so:

13(-1m+3)+2m

We add all the numbers together, and all the variables

2m+13(-1m+3)

We multiply parentheses

2m-13m+39

We add all the numbers together, and all the variables

-11m+39

Back to the equation:

-(-11m+39)



We get rid of parentheses

7m+11m-39-35=0

We add all the numbers together, and all the variables

18m-74=0

We move all terms containing m to the left, all other terms to the right

18m=74

m=74/18

m=4+1/9

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