7(m-8)=3(m+4)

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Solution for 7(m-8)=3(m+4) equation: 



7(m-8)=3(m+4)

We move all terms to the left:

7(m-8)-(3(m+4))=0

We multiply parentheses

7m-(3(m+4))-56=0



We calculate terms in parentheses: -(3(m+4)), so:

3(m+4)

We multiply parentheses

3m+12

Back to the equation:

-(3m+12)



We get rid of parentheses

7m-3m-12-56=0

We add all the numbers together, and all the variables

4m-68=0

We move all terms containing m to the left, all other terms to the right

4m=68

m=68/4

m=17

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