7(n+2)=3(n-6)

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Solution for 7(n+2)=3(n-6) equation: 



7(n+2)=3(n-6)

We move all terms to the left:

7(n+2)-(3(n-6))=0

We multiply parentheses

7n-(3(n-6))+14=0



We calculate terms in parentheses: -(3(n-6)), so:

3(n-6)

We multiply parentheses

3n-18

Back to the equation:

-(3n-18)



We get rid of parentheses

7n-3n+18+14=0

We add all the numbers together, and all the variables

4n+32=0

We move all terms containing n to the left, all other terms to the right

4n=-32

n=-32/4

n=-8

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