7(n+2)=4n+35

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Solution for 7(n+2)=4n+35 equation:


Simplifying
7(n + 2) = 4n + 35

Reorder the terms:
7(2 + n) = 4n + 35
(2 * 7 + n * 7) = 4n + 35
(14 + 7n) = 4n + 35

Reorder the terms:
14 + 7n = 35 + 4n

Solving
14 + 7n = 35 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
14 + 7n + -4n = 35 + 4n + -4n

Combine like terms: 7n + -4n = 3n
14 + 3n = 35 + 4n + -4n

Combine like terms: 4n + -4n = 0
14 + 3n = 35 + 0
14 + 3n = 35

Add '-14' to each side of the equation.
14 + -14 + 3n = 35 + -14

Combine like terms: 14 + -14 = 0
0 + 3n = 35 + -14
3n = 35 + -14

Combine like terms: 35 + -14 = 21
3n = 21

Divide each side by '3'.
n = 7

Simplifying
n = 7

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