7(n+3)-6(n-4)=19

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Solution for 7(n+3)-6(n-4)=19 equation:


Simplifying
7(n + 3) + -6(n + -4) = 19

Reorder the terms:
7(3 + n) + -6(n + -4) = 19
(3 * 7 + n * 7) + -6(n + -4) = 19
(21 + 7n) + -6(n + -4) = 19

Reorder the terms:
21 + 7n + -6(-4 + n) = 19
21 + 7n + (-4 * -6 + n * -6) = 19
21 + 7n + (24 + -6n) = 19

Reorder the terms:
21 + 24 + 7n + -6n = 19

Combine like terms: 21 + 24 = 45
45 + 7n + -6n = 19

Combine like terms: 7n + -6n = 1n
45 + 1n = 19

Solving
45 + 1n = 19

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-45' to each side of the equation.
45 + -45 + 1n = 19 + -45

Combine like terms: 45 + -45 = 0
0 + 1n = 19 + -45
1n = 19 + -45

Combine like terms: 19 + -45 = -26
1n = -26

Divide each side by '1'.
n = -26

Simplifying
n = -26

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