7(n+4)=2(3+4n)

Solution for 7(n+4)=2(3+4n) equation:

7(n+4)=2(3+4n)

We move all terms to the left:

7(n+4)-(2(3+4n))=0

We add all the numbers together, and all the variables

7(n+4)-(2(4n+3))=0

We multiply parentheses

7n-(2(4n+3))+28=0


We calculate terms in parentheses: -(2(4n+3)), so:

2(4n+3)

We multiply parentheses

8n+6

Back to the equation:

-(8n+6)


We get rid of parentheses

7n-8n-6+28=0

We add all the numbers together, and all the variables

-1n+22=0

We move all terms containing n to the left, all other terms to the right

-n=-22

n=-22/-1

n=+22