7(n-2)+8=3(n-4)-2

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Solution for 7(n-2)+8=3(n-4)-2 equation: 



7(n-2)+8=3(n-4)-2

We move all terms to the left:

7(n-2)+8-(3(n-4)-2)=0

We multiply parentheses

7n-(3(n-4)-2)-14+8=0



We calculate terms in parentheses: -(3(n-4)-2), so:

3(n-4)-2

We multiply parentheses

3n-12-2

We add all the numbers together, and all the variables

3n-14

Back to the equation:

-(3n-14)



We add all the numbers together, and all the variables

7n-(3n-14)-6=0

We get rid of parentheses

7n-3n+14-6=0

We add all the numbers together, and all the variables

4n+8=0

We move all terms containing n to the left, all other terms to the right

4n=-8

n=-8/4

n=-2

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