7(n-3)+11/6=18-(6+2n)/8

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Solution for 7(n-3)+11/6=18-(6+2n)/8 equation: 



7(n-3)+11/6=18-(6+2n)/8

We move all terms to the left:

7(n-3)+11/6-(18-(6+2n)/8)=0

We add all the numbers together, and all the variables

7(n-3)-(18-(2n+6)/8)+11/6=0

We multiply parentheses

7n-(18-(2n+6)/8)-21+11/6=0

We calculate fractions


7n+(-(18-(2n+6)*6)/()+()/()-21=0

We can not solve this equation

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