7(n-3)+3(n-4)=2

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Solution for 7(n-3)+3(n-4)=2 equation:


Simplifying
7(n + -3) + 3(n + -4) = 2

Reorder the terms:
7(-3 + n) + 3(n + -4) = 2
(-3 * 7 + n * 7) + 3(n + -4) = 2
(-21 + 7n) + 3(n + -4) = 2

Reorder the terms:
-21 + 7n + 3(-4 + n) = 2
-21 + 7n + (-4 * 3 + n * 3) = 2
-21 + 7n + (-12 + 3n) = 2

Reorder the terms:
-21 + -12 + 7n + 3n = 2

Combine like terms: -21 + -12 = -33
-33 + 7n + 3n = 2

Combine like terms: 7n + 3n = 10n
-33 + 10n = 2

Solving
-33 + 10n = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '33' to each side of the equation.
-33 + 33 + 10n = 2 + 33

Combine like terms: -33 + 33 = 0
0 + 10n = 2 + 33
10n = 2 + 33

Combine like terms: 2 + 33 = 35
10n = 35

Divide each side by '10'.
n = 3.5

Simplifying
n = 3.5

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