7(n-3)+4(2n-5=)

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Solution for 7(n-3)+4(2n-5=) equation: 



7(n-3)+4(2n-5=)

We move all terms to the left:

7(n-3)+4(2n-5-())=0

We multiply parentheses

7n+4(2n-5-())-21=0

We move all terms containing n to the left, all other terms to the right

7n+4(2n-5-())=21

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