7(n-3)11/6=18-(6+2n)/8

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Solution for 7(n-3)11/6=18-(6+2n)/8 equation: 



7(n-3)11/6=18-(6+2n)/8

We move all terms to the left:

7(n-3)11/6-(18-(6+2n)/8)=0

We add all the numbers together, and all the variables

7(n-3)11/6-(18-(2n+6)/8)=0

We calculate fractions


7n/()+(-(18-(2n+6)*6)/()=0



We calculate terms in parentheses: +(-(18-(2n+6)*6)/(), so:

-(18-(2n+6)*6)/(

We multiply all the terms by the denominator


-(18-(2n+6)*6)



We calculate terms in parentheses: -(18-(2n+6)*6), so:

18-(2n+6)*6

determiningTheFunctionDomain
-(2n+6)*6+18

We multiply parentheses

-12n-36+18

We add all the numbers together, and all the variables

-12n-18

Back to the equation:

-(-12n-18)



We get rid of parentheses

12n+18

Back to the equation:

+(12n+18)



We get rid of parentheses

7n/()+12n+18=0

We multiply all the terms by the denominator


7n+12n*()+18*()=0

We add all the numbers together, and all the variables

7n+12n*()=0

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