7(n-3)=4(2n-10)

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Solution for 7(n-3)=4(2n-10) equation: 



7(n-3)=4(2n-10)

We move all terms to the left:

7(n-3)-(4(2n-10))=0

We multiply parentheses

7n-(4(2n-10))-21=0



We calculate terms in parentheses: -(4(2n-10)), so:

4(2n-10)

We multiply parentheses

8n-40

Back to the equation:

-(8n-40)



We get rid of parentheses

7n-8n+40-21=0

We add all the numbers together, and all the variables

-1n+19=0

We move all terms containing n to the left, all other terms to the right

-n=-19

n=-19/-1

n=+19

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