7(n-5)+6(n+3)=11

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Solution for 7(n-5)+6(n+3)=11 equation:



7(n-5)+6(n+3)=11
We move all terms to the left:
7(n-5)+6(n+3)-(11)=0
We multiply parentheses
7n+6n-35+18-11=0
We add all the numbers together, and all the variables
13n-28=0
We move all terms containing n to the left, all other terms to the right
13n=28
n=28/13
n=2+2/13

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