7(n-5)+6(n+3)=2(11)

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Solution for 7(n-5)+6(n+3)=2(11) equation:


Simplifying
7(n + -5) + 6(n + 3) = 2(11)

Reorder the terms:
7(-5 + n) + 6(n + 3) = 2(11)
(-5 * 7 + n * 7) + 6(n + 3) = 2(11)
(-35 + 7n) + 6(n + 3) = 2(11)

Reorder the terms:
-35 + 7n + 6(3 + n) = 2(11)
-35 + 7n + (3 * 6 + n * 6) = 2(11)
-35 + 7n + (18 + 6n) = 2(11)

Reorder the terms:
-35 + 18 + 7n + 6n = 2(11)

Combine like terms: -35 + 18 = -17
-17 + 7n + 6n = 2(11)

Combine like terms: 7n + 6n = 13n
-17 + 13n = 2(11)

Multiply 2 * 11
-17 + 13n = 22

Solving
-17 + 13n = 22

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 13n = 22 + 17

Combine like terms: -17 + 17 = 0
0 + 13n = 22 + 17
13n = 22 + 17

Combine like terms: 22 + 17 = 39
13n = 39

Divide each side by '13'.
n = 3

Simplifying
n = 3

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