7(p+2)=2(3p+1)-11

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Solution for 7(p+2)=2(3p+1)-11 equation: 



7(p+2)=2(3p+1)-11

We move all terms to the left:

7(p+2)-(2(3p+1)-11)=0

We multiply parentheses

7p-(2(3p+1)-11)+14=0



We calculate terms in parentheses: -(2(3p+1)-11), so:

2(3p+1)-11

We multiply parentheses

6p+2-11

We add all the numbers together, and all the variables

6p-9

Back to the equation:

-(6p-9)



We get rid of parentheses

7p-6p+9+14=0

We add all the numbers together, and all the variables

p+23=0

We move all terms containing p to the left, all other terms to the right

p=-23

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