7(q+2)=35

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Solution for 7(q+2)=35 equation: 



7(q+2)=35

We move all terms to the left:

7(q+2)-(35)=0

We multiply parentheses

7q+14-35=0

We add all the numbers together, and all the variables

7q-21=0

We move all terms containing q to the left, all other terms to the right

7q=21

q=21/7

q=3

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