7(r+1)=28+4r

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Solution for 7(r+1)=28+4r equation: 



7(r+1)=28+4r

We move all terms to the left:

7(r+1)-(28+4r)=0

We add all the numbers together, and all the variables

7(r+1)-(4r+28)=0

We multiply parentheses

7r-(4r+28)+7=0

We get rid of parentheses

7r-4r-28+7=0

We add all the numbers together, and all the variables

3r-21=0

We move all terms containing r to the left, all other terms to the right

3r=21

r=21/3

r=7

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