7(r+5)+3=-9-3(r-6)

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Solution for 7(r+5)+3=-9-3(r-6) equation: 



7(r+5)+3=-9-3(r-6)

We move all terms to the left:

7(r+5)+3-(-9-3(r-6))=0

We multiply parentheses

7r-(-9-3(r-6))+35+3=0



We calculate terms in parentheses: -(-9-3(r-6)), so:

-9-3(r-6)

determiningTheFunctionDomain
-3(r-6)-9

We multiply parentheses

-3r+18-9

We add all the numbers together, and all the variables

-3r+9

Back to the equation:

-(-3r+9)



We add all the numbers together, and all the variables

7r-(-3r+9)+38=0

We get rid of parentheses

7r+3r-9+38=0

We add all the numbers together, and all the variables

10r+29=0

We move all terms containing r to the left, all other terms to the right

10r=-29

r=-29/10

r=-2+9/10

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