7(r-2)-5=2(r+6)+4

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Solution for 7(r-2)-5=2(r+6)+4 equation: 



7(r-2)-5=2(r+6)+4

We move all terms to the left:

7(r-2)-5-(2(r+6)+4)=0

We multiply parentheses

7r-(2(r+6)+4)-14-5=0



We calculate terms in parentheses: -(2(r+6)+4), so:

2(r+6)+4

We multiply parentheses

2r+12+4

We add all the numbers together, and all the variables

2r+16

Back to the equation:

-(2r+16)



We add all the numbers together, and all the variables

7r-(2r+16)-19=0

We get rid of parentheses

7r-2r-16-19=0

We add all the numbers together, and all the variables

5r-35=0

We move all terms containing r to the left, all other terms to the right

5r=35

r=35/5

r=7

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