7(r-4)-6(r-1)=2(R+3)

Solution for 7(r-4)-6(r-1)=2(R+3) equation:

Simplifying
7(r + -4) + -6(r + -1) = 2(R + 3)

Reorder the terms:
7(-4 + r) + -6(r + -1) = 2(R + 3)
(-4 * 7 + r * 7) + -6(r + -1) = 2(R + 3)
(-28 + 7r) + -6(r + -1) = 2(R + 3)

Reorder the terms:
-28 + 7r + -6(-1 + r) = 2(R + 3)
-28 + 7r + (-1 * -6 + r * -6) = 2(R + 3)
-28 + 7r + (6 + -6r) = 2(R + 3)

Reorder the terms:
-28 + 6 + 7r + -6r = 2(R + 3)

Combine like terms: -28 + 6 = -22
-22 + 7r + -6r = 2(R + 3)

Combine like terms: 7r + -6r = 1r
-22 + 1r = 2(R + 3)

Reorder the terms:
-22 + 1r = 2(3 + R)
-22 + 1r = (3 * 2 + R * 2)
-22 + 1r = (6 + 2R)

Solving
-22 + 1r = 6 + 2R

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + 1r = 6 + 22 + 2R

Combine like terms: -22 + 22 = 0
0 + 1r = 6 + 22 + 2R
1r = 6 + 22 + 2R

Combine like terms: 6 + 22 = 28
1r = 28 + 2R

Divide each side by '1'.
r = 28 + 2R

Simplifying
r = 28 + 2R