7(r-5)+5=2(2r-3)-6

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Solution for 7(r-5)+5=2(2r-3)-6 equation: 



7(r-5)+5=2(2r-3)-6

We move all terms to the left:

7(r-5)+5-(2(2r-3)-6)=0

We multiply parentheses

7r-(2(2r-3)-6)-35+5=0



We calculate terms in parentheses: -(2(2r-3)-6), so:

2(2r-3)-6

We multiply parentheses

4r-6-6

We add all the numbers together, and all the variables

4r-12

Back to the equation:

-(4r-12)



We add all the numbers together, and all the variables

7r-(4r-12)-30=0

We get rid of parentheses

7r-4r+12-30=0

We add all the numbers together, and all the variables

3r-18=0

We move all terms containing r to the left, all other terms to the right

3r=18

r=18/3

r=6

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