7(r-8)=3(r+4)

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Solution for 7(r-8)=3(r+4) equation: 



7(r-8)=3(r+4)

We move all terms to the left:

7(r-8)-(3(r+4))=0

We multiply parentheses

7r-(3(r+4))-56=0



We calculate terms in parentheses: -(3(r+4)), so:

3(r+4)

We multiply parentheses

3r+12

Back to the equation:

-(3r+12)



We get rid of parentheses

7r-3r-12-56=0

We add all the numbers together, and all the variables

4r-68=0

We move all terms containing r to the left, all other terms to the right

4r=68

r=68/4

r=17

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