7(s+3)=5s+27

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Solution for 7(s+3)=5s+27 equation: 



7(s+3)=5s+27

We move all terms to the left:

7(s+3)-(5s+27)=0

We multiply parentheses

7s-(5s+27)+21=0

We get rid of parentheses

7s-5s-27+21=0

We add all the numbers together, and all the variables

2s-6=0

We move all terms containing s to the left, all other terms to the right

2s=6

s=6/2

s=3

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