7(s-30)-40=3(50+s)

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Solution for 7(s-30)-40=3(50+s) equation: 



7(s-30)-40=3(50+s)

We move all terms to the left:

7(s-30)-40-(3(50+s))=0

We add all the numbers together, and all the variables

7(s-30)-(3(s+50))-40=0

We multiply parentheses

7s-(3(s+50))-210-40=0



We calculate terms in parentheses: -(3(s+50)), so:

3(s+50)

We multiply parentheses

3s+150

Back to the equation:

-(3s+150)



We add all the numbers together, and all the variables

7s-(3s+150)-250=0

We get rid of parentheses

7s-3s-150-250=0

We add all the numbers together, and all the variables

4s-400=0

We move all terms containing s to the left, all other terms to the right

4s=400

s=400/4

s=100

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