7(t+2)+10=6(t+3)+9

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Solution for 7(t+2)+10=6(t+3)+9 equation:



7(t+2)+10=6(t+3)+9
We move all terms to the left:
7(t+2)+10-(6(t+3)+9)=0
We multiply parentheses
7t-(6(t+3)+9)+14+10=0
We calculate terms in parentheses: -(6(t+3)+9), so:
6(t+3)+9
We multiply parentheses
6t+18+9
We add all the numbers together, and all the variables
6t+27
Back to the equation:
-(6t+27)
We add all the numbers together, and all the variables
7t-(6t+27)+24=0
We get rid of parentheses
7t-6t-27+24=0
We add all the numbers together, and all the variables
t-3=0
We move all terms containing t to the left, all other terms to the right
t=3

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